mols Ca(OH)2 = grams/molar mass = ?
mols CaCl2 = mols Ca(OH)2 from the equation (1 mol Ca(OH)2 = 1 mol CaCl2)
g CaCl2 = mols CaCl2 x molar mass CaCl2.
This is the theoretical yield (TY). The actual yield (AY) is given in the problem as 6.74 g.
%yield = (AY/TY)*100 = ?
lime, Ca(OH)2 can be used to neutralize an acid spill.A 5.06-g sample of Ca(OH)reacts with excess of hydrochloric acid:6.74 g of calcium chloride is collected what is the percent yield of this experiment
Ca(OH)2 + 2HCI ====> CaCl2 + 2H2O
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