lim (-x+10)/(x©÷-100)
x¡æ10
is this correct?
1/20
4 answers
I do not understand your symbols.
lim (-x+10)/(x^2-100)
as x approaches 10
is 1/20 correct
as x approaches 10
is 1/20 correct
-(x-10) /[(x-10)(x+10)]
= -1/(x+10)
---> -1/20
= -1/(x+10)
---> -1/20
I get -1/20 as the limit.