lim x->1 (x^47-1)/(x^9-1)

Question

With what method do I factor them with? Pascal triangle?

Answer 1

They are standard forms, (x^n-1) has (x-1) as a factor, and (x^(n-1)+x^(n-2)+....x²+x+1) as the other factor.

Can you take it from here?

Answer 2

Note: the above factoring applies only when n is odd!

Answer 3

Is the answer 47/9?

Answer 4

Correct, keep up the good work!

Answer 5

Thank you so much! :)