Asked by tish

lim x→0 of [tan(3x^2) + sin^2(5x)] / (x^2)
Answered by Damon
Hey, I did the other one, try series approach on this one too.
Answered by Damon
by the way tangent of small angle approaches sine of that small angle :) theta + theta^2/2 .......
Answered by Steve
recall that lim x->0 of sinx/x and tanx/x = 1

You have

tan(3x^2)/x^2 + sin^2(5x)/x^2
= 3*tan(3x^2)/(3x^2) + 25(sin5x/5x)^2
--> 3+25
= 28
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