lim x→0 of [2-cos3x-cos4x]/(x)

Answer 1

as y--->0
cos y = 1 - y^2/2 + ........

numerator:
2 - 1 +(1/2)(9)x^2 -1 +(1/2)(16)x^2

0 + (25/2)x^2 oh my
now divide by x

25 x/2
goes to 0 as x goes to 0