lim (x->0.5 from the left)((2x-1)/|(2x^3-x^2)| = -4
I would have thought positive four. How can this be?
2 answers
Look at the denominator. For values of x>1/2, the x^3 term donminates. However, for values less than 1/2, the x^2 term donminates and will force the denominator negative.
I see that now. Thank you.