do you mean
(√(1+t)-√(1-t))/t ?
That is indeed 0/0
"rationalizing" the numerator, we have
(√(1+t)-√(1-t))(√(1+t)+√(1-t))
--------------------------------
t (√(1+t)+√(1-t))
(1+t)-(1-t)
----------------
t (√(1+t)+√(1-t))
--> 2/(1*(√2+0)) = 2/√2 = √2
lim
t--->0
square rooted (1+t) - square rooted (1-t)/t
this is what i have so far is the conjugates of the square root of 1+t and 1-t
which would be square root of 1+t + square root of 1-t/t(square rooted (1+t)(1-t)
the numerator is not canceling out.......
1 answer