arcsin(x) cotx = arcsin(x)/tanx
you have 0/0, so take derivatives
1/√(1-x^2) / sec^2x → 1/1 = 1
lim (arccsinx)(cotx)
x-->0+
How do I solve this limit using L'Hopital's rule?
2 answers
Thank you!
x-->0+
How do I solve this limit using L'Hopital's rule?
2 answers