Light travel through a transparent oil enters into glass of refractive index 1.5. If the refractive index of glass with respect to oil is 1.25 what is the refractive index of oil?

Answer 1

Let the refractive index of oil be represented as n.

According to Snell's Law,
n1 * sinθ1 = n2 * sinθ2

Where,
n1 = refractive index of oil = n
n2 = refractive index of glass = 1.5
Refractive index of glass with respect to oil = 1.25

sinθ1 = sinθ2 (since light travels along the perpendicular to the interface between oil and glass)

n * sinθ = 1.25 * sinθ

n = 1.25

Therefore, the refractive index of oil is 1.25.