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Light passes from air into water at an angle of incidence of 40.4°. Determine the angle of refraction in the water.

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I hope you have heard of Snell's law.

N(air)*sin theta(in air)
= N(water)*sin theta (in water)
sin theta (in water) = (1/1.33)sin 40.4 = 0.487

Solve for theta in water

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