To meet their goal of raising at least $300 while selling no more than 80 items, we can represent the number of cookies sold as \( c \) and the number of muffins sold as \( m \). We need to satisfy the following conditions:
- Total revenue: \( 3c + 5m \geq 300 \)
- Total items: \( c + m \leq 80 \)
Let’s go through some possible combinations of cookies and muffins:
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Combination A: \( c = 50, m = 30 \)
- Total items: \( 50 + 30 = 80 \) (this is within the limit)
- Total revenue: \( 3(50) + 5(30) = 150 + 150 = 300 \) (this meets the revenue target)
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Combination B: \( c = 20, m = 70 \)
- Total items: \( 20 + 70 = 90 \) (this exceeds the limit)
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Combination C: \( c = 40, m = 40 \)
- Total items: \( 40 + 40 = 80 \) (this is within the limit)
- Total revenue: \( 3(40) + 5(40) = 120 + 200 = 320 \) (this meets the revenue target)
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Combination D: \( c = 0, m = 60 \)
- Total items: \( 0 + 60 = 60 \) (this is within the limit)
- Total revenue: \( 3(0) + 5(60) = 0 + 300 = 300 \) (this meets the revenue target)
Each of these combinations (A, C, and D) successfully achieves at least $300 in revenue while keeping the total items sold within the limit of 80. Any of these could be viable options for Liam's bake sale. If you provide specific combinations to choose from, I can also analyze those.