Let's analyze the given reaction and what happens under different disturbances:
Reaction:
Reactant 1 + Reactant 2 ⇔ Product A + Heat
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Removal of Product A:
This disturbance will shift the equilibrium to the right (forward reaction) to replace the removed Product A.
Shift: Favors Forward Reaction (Shift right) -
Addition of heat:
Since heat is a product in this reaction, adding heat will shift the equilibrium to the left (reverse reaction) to absorb the excess heat.
Shift: Favors Reverse Reaction (Shifts left) -
Addition of Reactant 1:
Adding more Reactant 1 will shift the equilibrium to the right (forward reaction) to use up the added reactant.
Shift: Favors Forward Reaction (Shift right) -
Removal of Reactant 2:
Removing Reactant 2 will shift the equilibrium to the left (reverse reaction) because there are fewer reactants available to form Product A.
Shift: Favors Reverse Reaction (Shifts left) -
Removal of heat:
Since heat is a product, removing heat will shift the equilibrium to the right (forward reaction) to produce more heat.
Shift: Favors Forward Reaction (Shift right)
Question 2: The forward reaction can be considered:
Since heat is released as a product when Reactant 1 and Reactant 2 react to form Product A, this indicates that the reaction is exothermic.
Response: Exothermic