a = -32 ft/s^2
v = 50 -32 t
h = 6 + 50 t - 16 t^2
find t when h = 0 (the positive answer)
max height is when v = 0, find t and h then.
Let’s suppose you throw a ball straight up with an initial speed of 50 feet per second from a height of 6 feet.
a.Find the parametric equations that describe the motion of the ball as a function of time.
b.How long is the ball in the air?
c.Determine when the ball is at maximum height. Find its maximum height.
i haven't got the slightest idea of how to do this.
1 answer
1 answer