lets say two capacitors C1 and C2 1uF each are connected in series with a voltage source 5v. One of the capacitors C2 has an initial voltage of 1v and the other has no charge on it initially.What is the final voltages across the capacitor C2?

Answer 1

Ct = (1*1)/(1+1) = 1/2 = 0.5uF. = Tot.
capacitance.

Qt=Q1 = Q2 = Ct*E = 0.5*5 = 2.5uC.

V2 = Q2/C2 = 2.5/1 = 2.5 Volts.

Answer 2

what about the initial 1v on capacitor c2. Since the source is at 5v ,this capacitor charge cannot get redistributed.Hence should it not add to the final value across c2? can somebody throw some light on this.?