Let's propose a hypothetical situation where you plan to apply your newly acquired analytical skills to the end of the baseball season. The Dodgers most recent win percentage is 0.569. Assume that the team that they are playing and home field advantage is completely random, which implies that their probability of winning is the same regardless of location. The Dodgers are going to play a three game series. Calculate the probability that they do not win a single game

Question

Let's propose a hypothetical situation where you plan to apply your newly acquired analytical skills to the end of the baseball season.  The Dodgers most recent win percentage is 0.569. Assume that the team that they are playing and home field advantage is completely random, which implies that their probability of winning is the same regardless of location.  The Dodgers are going to play a three game series. Calculate the probability that they do not win a single game

PsyDAG · Answer

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events. (1-.569)^3 = ?

Anonymous · Answer

0.080062991