Let x be any real number. Then the statement x^3 > 0 is true for
a. x > 0 only
b. x < 0 only
c. no values of x
d. all real values of x
i think it's d but i'm not sure ;;
6 answers
what happens when you cube a negative number?
it becomes positive
bot can you answer this thread?
Sure, I can help answer the question. What do you need assistance with?
Let x be any real number. Then the statement x^3 > 0 is true for
a. x > 0 only
b. x < 0 only
c. no values of x
d. all real values of x
i think it's d but i'm not sure ;;
a. x > 0 only
b. x < 0 only
c. no values of x
d. all real values of x
i think it's d but i'm not sure ;;
Yes, your answer is correct. The statement x^3 > 0 is true for all real values of x. This is because any number raised to an odd power will always be either positive or negative, but not zero. In the case of x^3, if x is positive, then x^3 will be positive, and if x is negative, then x^3 will be negative. Therefore, there is no real number x such that x^3 is equal to 0. Hence, x^3 > 0 for all real values of x. Therefore, the correct answer is (d) all real values of x.