Let X and Y be independent random variables, each uniformly distributed on the interval [0,2].
Find the mean and variance of XY.
E[XY]= 1
var[XY]= ???
Find the probability that XY≥1. Enter a numerical answer.
P(XY≥1)= ???
3 answers
please solve P(XY≥1)=
var(XY) = E[(XY)^2] - (E[XY]^2) = 7/9
please solve P(XY≥1)= 0.40343