Question
Let us compute the t-SNE output for the isoceles triangle as in the previous problem.
Recall we are given 3 points in 2 dimensions, as shown in the figure below:
\mathbf{x}^{(1)} the center node , and \mathbf{x}^{(2)} and \mathbf{x}^{(3)} the boundary nodes. The 2 boundary nodes are at distance A to the center node, and are farther away from each other, at distance B (B>A) than they are from the center node. Here, we are given A=1, and B=\sqrt{2}.
The distribution \mathbf{P} in 2D remains the same as before, and for this small example, we will again try to minimize \text {KL}(\mathbf{P}||\mathbf{Q}) by solving for \text {KL}(\mathbf{P}||\mathbf{Q})=0.
What is different from before is that we will use the t-distribution to define \mathbf{Q} in the target space.
Assume again that the projection onto 1D is as follow with unknown distance a between the center and boundary nodes, but a distance 2a between the boundary nodes.
Write down q_{ij} in terms of the distance a and find a such that q_{12}=p_{12}, giving \text {KL}(\mathbf{P}||\mathbf{Q})=0.
(Enter an answer accurate to at least 3 decimal places.)
a=\quad
Recall we are given 3 points in 2 dimensions, as shown in the figure below:
\mathbf{x}^{(1)} the center node , and \mathbf{x}^{(2)} and \mathbf{x}^{(3)} the boundary nodes. The 2 boundary nodes are at distance A to the center node, and are farther away from each other, at distance B (B>A) than they are from the center node. Here, we are given A=1, and B=\sqrt{2}.
The distribution \mathbf{P} in 2D remains the same as before, and for this small example, we will again try to minimize \text {KL}(\mathbf{P}||\mathbf{Q}) by solving for \text {KL}(\mathbf{P}||\mathbf{Q})=0.
What is different from before is that we will use the t-distribution to define \mathbf{Q} in the target space.
Assume again that the projection onto 1D is as follow with unknown distance a between the center and boundary nodes, but a distance 2a between the boundary nodes.
Write down q_{ij} in terms of the distance a and find a such that q_{12}=p_{12}, giving \text {KL}(\mathbf{P}||\mathbf{Q})=0.
(Enter an answer accurate to at least 3 decimal places.)
a=\quad
Answers
There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.