let the point be T(x,y)
then (x+3)/(5-x) = 1/3
3x+9 = 5-x
x = -1
do the same for the y
(y-7)/(-12-y) = 1/3
3y-21 = -12-y
y = 9/4
Let P be (-3,7) and Q be (5,-12)
Find the point T on line segment PQ such that PT/TQ = 1/3
How would I go about solving this problem?
Thank you so much!
5 answers
Could you try to explain it a little more?
I was simply using your given ratio.
(change in x's from P to T)/(change in x's from T to Q) = 1/3
do the same for the y's
You can use this method to divide a line segment into any given ratio.
(change in x's from P to T)/(change in x's from T to Q) = 1/3
do the same for the y's
You can use this method to divide a line segment into any given ratio.
e endpoints of $\overline{AB}$ are $A(-4,\ -8)$ and $B(-1,\ 4)$ . Find the coordinates of the midpoint $M$ .
The coordinates of the midpoint $M$ are (
,
)
The coordinates of the midpoint $M$ are (
,
)
e endpoints of $\overline{AB}$ are $A(-4,\ -8)$ and $B(-1,\ 4)$ . Find the coordinates of the midpoint $M$ .
The coordinates of the midpoint $M$ are (
,
)
The coordinates of the midpoint $M$ are (
,
)