Let line l_1 be the graph of 5x + 8y = -9. Line l_2 is perpendicular to line l_1 and passes through the point (10,10). If line l_2 is the graph of the equation y=mx +b, then find m+b.
3 answers
Please help! This is overdue and if I don't turn it in I fail!
in
https://www.jiskha.com/display.cgi?id=1504542568
looks like I had a typo from
8x - 5y = 30 <---- ok here
so 5y = 8x - 30 , to
y = (8/5) x - 6
so m + b = 8/5 - 6
= -22/5
you should have caught my error instead of saying you got the same thing
https://www.jiskha.com/display.cgi?id=1504542568
looks like I had a typo from
8x - 5y = 30 <---- ok here
so 5y = 8x - 30 , to
y = (8/5) x - 6
so m + b = 8/5 - 6
= -22/5
you should have caught my error instead of saying you got the same thing
L1 has slope -5/8
L2 must have slope 8/5
So, the point-slope form of L2 is
y-10 = 8/5 (x-10)
y = 8/5 x - 6
m+b = 8/5 - 6 = -22/5
L2 must have slope 8/5
So, the point-slope form of L2 is
y-10 = 8/5 (x-10)
y = 8/5 x - 6
m+b = 8/5 - 6 = -22/5