let h(x)=x+6 and g(x)=x^(2)-4x+2

find h (x) g(x)
x³+2x²-22x+12
x²-3x+8
x³+5x²+24x+12
x² +5x +8

1 answer

To find h(x)g(x), we need to multiply the two functions:

h(x)g(x) = (x+6)(x^2-4x+2)

Using the distributive property, we can multiply each term in the first expression by each term in the second expression:

h(x)g(x) = x(x^2-4x+2) + 6(x^2-4x+2)

Simplifying further:

h(x)g(x) = x^3 - 4x^2 + 2x + 6x^2 - 24x + 12

Combining like terms:

h(x)g(x) = x^3 + 2x^2 - 22x + 12

Therefore, h(x)g(x) is equal to x^3 + 2x^2 - 22x + 12.