h' = df/dg * dg/dx
at x = 2
dg/dx = -2 and g = 7
df/dg at g = 7 = -8
so
-8 * -2 = + 16
that is how, you do the next
Let H(x)=F(G(x)) and J(x)=F(x)/G(x).
Suppose
F(7)=4, F′(7)=−8
G(7)=3, G′(7)=−5
G(2)=7, G′(2)=−2
then
H′(2)=
J′(7)=
2 answers
Thank you Damon! :)