Let g(x)={x^2-x-2 if x is not equal to 1

Question

{0 if x=1

Answer 1

ok.

there is certainly a break at x=1.

Answer 2

Srry the question is incomplete...

please help with these questions
a. Is g(x) continuous at x=1
b. What type of discontinuity does it have

Answer 3

lim (x->1) = -2
g(1) = 0

So, there is a jump discontinuity. It is not removable, since g(1) is defined, but is not the same as the limit from both sides.