I think it's 0.
Look at the graph. There's plenty of graphers online.
But since the interval of the normal cos function is 1, -1, cos(x)-1 is 0, -1
which means 0 is the biggest value
Let g(x)=|cos x-1|. The maximum value attained by g on the closed interval [0, 2pi] is for x equal to
A) -1
B) 0
C) pi/2
D) 2
E) pi
I think its pi/2 but I'm not sure at all.
2 answers
look... im not sure as well about which one it is, but im sure that its not C, D or E.... cause just like the guy above said, the interval of the normal cos function will always be 1,-1... so u wouldnt be able to get those values.... the maximum would be 0 and the lowest would be -2...so yea... its most probably 0