Asked by slayrat
                let g(x)=5x-2l and h(x)=x^2+1. Find the value of each expression. (h∘g)(-1)
            
            
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    To find (h∘g)(-1), we need to first evaluate g(-1) and then use that result as the input for h. 
g(x) is defined as 5x-2l, so g(-1) = 5(-1) - 2l = -7.
Now that we have g(-1) = -7, we can find (h∘g)(-1) by plugging it into h:
(h∘g)(-1) = h(g(-1)) = h(-7) = (-7)^2 + 1 = 50.
Therefore, (h∘g)(-1) = 50.
    
g(x) is defined as 5x-2l, so g(-1) = 5(-1) - 2l = -7.
Now that we have g(-1) = -7, we can find (h∘g)(-1) by plugging it into h:
(h∘g)(-1) = h(g(-1)) = h(-7) = (-7)^2 + 1 = 50.
Therefore, (h∘g)(-1) = 50.
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