Let g(s)=1/(s-2) on the interval [0,1]. Find the absolute maximum and absolute minimum of g(s) on this interval.

Question

The absolute max occurs at s=.
The absolute min occurs at s=

Answer 1

hint:
find g(0) and g(1)
find where g'(s) = 0, then evaluate g there.

pick the min and max of those values.

Answer 2

i got maximum to be -¼ and minimum to be -1 and i got it wrong