Let f(x) = x + 4 and h(x) = 4x - 1

Question

Find a function "g" such that "g compose of f equals to h"

g(f(x) = h
g(f) = h
g(x + 4) = 4x - 1
g = (4x - 1) / (x + 4)

But my answer is wrong, how do I retrieve the right answer?

By the way, the right answer is "g(x) = 4x - 17"

Answer 1

ok up to g(x+4) = 4x-1

(the (x+4) in this notation is not a multiplier, looks like you treated it that way in your next line, how about this......

let x = k-4 then
g(x+4) = 4x - 1 becomes
g(k-4+4) = 4(k-4) - 1
g(k) = 4k - 16 - 1
or g(k) = 4k - 17 or
g(m) = 4m - 17 or whatever variable you want, so..
g(x) = 4x - 17