Replace |x-3| with x-3 and solve. Accept only solutions for which x>3
Then replace |x-3| with 3-x and solve again. Accept only solutions for which x<3
Let f(x)=x+2 Ix-3I and g(x)=3x-1
Find all solutions to the equation f(g(x))=-4x
So this is what I did...
(3x-1)+2 I(3x-1)-3I=-4x
(3x-1)+2 I3x-4I=-4x
This is where I got stuck. What do I do with the absolute value? and this part?(3x-1)+2=3x+1 ??
3 answers
Solve it in regions:
a) when 3x>4 or x>4/3
then 3x-1+6x-8=-4x
13x=9
x=9/13 check that. IF so, then not a solution, because x is not>4/3
b) when 3x<4 or x<4/3
then 3x-1-6x+2=-4x
x=1 which is true, because x<4/3
check my figuring.
a) when 3x>4 or x>4/3
then 3x-1+6x-8=-4x
13x=9
x=9/13 check that. IF so, then not a solution, because x is not>4/3
b) when 3x<4 or x<4/3
then 3x-1-6x+2=-4x
x=1 which is true, because x<4/3
check my figuring.
Thanks you! I get it now!
5 answers