Let f(x)=|x+1|/(x^(2)-1). Is f continuous? If not,classify any points of discontinuity as infinite, jump, or removable. Sketch the graph of y=f(x) for -4<=x<=4

Answer 1

since x^2-1=0 at x = ±1, f is not continuous.

For any other values,
f(x) = 1/(x-1) when x > -1
f(x) = -1/(x-1) for x < -1

evaluate the left and right limits near 1 and -1 to determine the nature of the discontinuities.