[1/(4+h+12) - 1/(4+12) ] / h
[ 1/(16+h) - 1/16 ] / h
[ 16 - 16-h ]/[(16+h)(16)h]
-h / [(256+16h)h]
-1 / [16 h + 256]
Let f(x) be the function 1/[x+12] . Then the quotient [f(4+h)-f(4)]/h
can be simplified to for: -1/[ah+b]
a=
b=
2 answers
Plug and chug :)