Factor it first
(x+3)(x+3) [4x -(x+3)] = 0
(x+3)(x+3)[3x-3] = 0
x = -3
x = -3
x = +1
Let f(x)= 4x(x+3)^2 - (x+3)^3 and find the values of x that correspond to f(x)=0.
2 answers
Thank you!
2 answers