Let f(x)=(-3x^2+6)^4(9x^2+7)^14, Find f'(x).

Question

f'(x)= (-3^2+6)^4 d/dx(9x^2+7)^14+(9x^2+7) d/dx(-3x^2+6)^4
=(-3x^2+6)x14(9x^2+7)^13 d/dx(9x^2+7)+(9x^2+7)^14x4(-3x^2+6)^3 d/dx(-3x^2+6)
=14(-3x+6)^4(9x^+7)^13 (18x)+ 4(9x^2+7)(-3x^2+6)^3 (-6x)

Answer 1

i got stuck

Answer 2

Start with the product rule, and take it slowly.

(d/dx)[(-3x^2+6)^4(9x^2+7)^14]
=(d/dx)[(-3x^2+6)^4](9x^2+7)^14 + (-3x^2+6)^4 (d/dx)[(9x^2+7)^14]
=4(-3x^2+6)^3 (d/dx)[-3x^2+6](9x^2+7)^14 + (-3x^2+6)^4*14(9x^2+7)^13(d/dx)[9x^2+7)
=4(-3x^2+6)^3 (-6x) + (-3x^2+6)^4*14(9x^2+7)^13 (18x)
Now take out the common factors (-3x^2+6)^3(9x^2+7)^13 to get

=(-3x^2+6)^3(9x^2+7)^13[4(-6x)(9x^2+7) + (-3x^2+6)14(18x)]
=(-3x^2+6)^3(9x^2+7)^13[-216x^3+168x + -756x^3+1512x]
=(-3x^2+6)^3(9x^2+7)^13[-972x^3+1344x]
=(-3x^2+6)^3(9x^2+7)^13(-12x)(81x^2-112)
=324x(x^2-2)^3(9x^2+7)^13(81x^2-112)

Answer 3

hey how u get 324x?

Answer 4

(-3x^2+6)^3(9x^2+7)^13(-12x)(81x^2-112)
=3^3(-12x)(-2+x^2)^3(9x^2+7)^13(81x^2-112)
=27*12x(x^2-2)^3(9x^2+7)^13(81x^2-112)
=324x(x^2-2)^3(9x^2+7)^13(81x^2-112)

Answer 5

i got it thanks

Answer 6

You're welcome! :)