I guess you mean
d^3y/dt^3 = 5 t + 10 t^-(1/2)
d^2y/dt^2 = (5/2)t^2 + (20/3)t^(3/2) + C
dy/dt = (5/6)t^3 + (40/15)t^(5/2) +C t+D
and so forth
Let f'''(t) = 5 t + 10 \sqrt{t}.
(a) Find the most general formula for f''(t). If an arbitrary constant must be used here, use an upper-case "C".
f''(t) =
(b) Based on your answer to (a), find the most general formula for f'(t). If another new arbitrary constant must be used here, use an upper-case "D".
f'(t) =
(c) Based on your answer to (b), find the most general formula for f(t). If another new arbitrary constant must be used here, use an upper-case "E".
f(t) =
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