Let f be the function defined by

f(x) =

x^2 if x<0

square root x if 0 ≤ x <1

2-x if 1 ≤ x< 2

x-3 if x ≥ 2

For what numbers x is f not continuos?

1 only
2 only
0 and 2 only
1 and 2 only

4 answers

0 is ok f(0) = 0
1 is ok, f(1) = 1
2 is NOT ok, f(2) = 0 and -1
If 0 and 1 is okay which answer would I Pick? It wouldnt be C or D
Nevermind it says not Continuous. So do I just plug in these numbers to each equation? Like Im confused how to solve it
If you get more than one value of f(x) for any x, the value changes instantly there. That is discontinuous. so if x = 2, tragedy.