Let f be the function defined by f(x)=2x+3e−5x, and let g be a differentiable function with derivative given by g′(x)=1x+4cos(5x). It is known that limx→∞g(x)=∞. The value of limx→∞f(x)g(x) is

Answer 1

g(x) = 1/2 x^2 + 4/5 sin(5x) + C
Since f→∞ and g→∞ then f*g→∞

Answer 2

jill urseld :)