Let f be the function defined by f(x)=2sinx+cosx ?

The average rate of change of f over the interval [0,b] is 0.05, where b>0 . Which of the following is an equation that could be used to find the value of b?

A) f(b)=0.05

B) f(b)−f(0)=0.05

C: (f(b)−f(0))/b−0=0.05

D: (f(b)+f(0))/2=0.05

3 answers

as always, the average rate of change over [a,b] is
(f(b) - f(a)) / (b-a)
So plug in your numbers.
So what’s the answer
d
Similar Questions
  1. I'm stuck on this problem and I dont know how to even start it...Let f be the function defined by f(x)=2sinx+cosx. The average
    1. answers icon 1 answer
  2. hey, i would really appreciate some help solving for x when:sin2x=cosx Use the identity sin 2A = 2sinAcosA so: sin 2x = cos x
    1. answers icon 0 answers
  3. The function f is defined asf(x) = -2sinx ; -π≤x≤-π/2 = asinx + b ; -π/2<x<π/2 = cosx ; π/2≤x≤π If f(x) is
    1. answers icon 1 answer
  4. Solve for x in the interval 0<=x<360:1. 2sin2x+cosx =0 2. cos2x=-2sinx 3. tanx=2sinx 4. 3cos2x+cosx+2=0
    1. answers icon 0 answers
more similar questions