y(6) = 36 - 72 = -36
y(5) = 25 - 60 = -35
dy/dx = [(-36) - (-35)]/(6-5)
= -1
same way for next 2
eg for x = 5 to 5.1
y(5.1) = -35.19
y(5) = -35
dy/dx = [-35.19 -(-35)]/(5.1-5)
= -1.9
(b) y' = 2x - 12
at x = 5
y' = 10-12 = -2
Let f be defined as follows.
y=f(x)=x^2-12x
(a) Find the average rate of change of y with respect to x in the following intervals.
from x = 5 to x = 6 ??
from x = 5 to x = 5.5 ??
from x = 5 to x = 5.1 ??
(b) Find the (instantaneous) rate of change of y at x = 5.
??
1 answer
1 answer