Let f(3) = 0, f '(3) = 6, g(3) = 1, and g '(3) = 1/3. If h(x) = f(x)*g(x), find h '(3).

Answer 1

Use the rule of products:
h'(x)
=d(f(x)*g(x))/dx
=f(x)*g'(x)+f'(x)*g(x)

For h'(3), substitute f(3),g'(3),f'(3) and g(3) above to evaluate.

Post your answer for a check if you wish.

Answer 2

6(h - 3) if h = -5