Let f:{0,1}->{0,1} with f(101)=1 and f(x)=0 for x ≠ 101 . In this question, we will run through two iterations of the algorithm.

(a) What is the superposition after the initialization step? Note that you can describe the superposition Σαx|x> by specifying two numbers α101 and αx for x ≠ 101 .

- α101=
- αx for x ≠ 101 =

(b) After the phase inversion in iteration 1?

- α101=
- αx for x ≠ 101 =

(c) After the inversion about mean in iteration 1?

- α101=
- αx for x ≠ 101 =

(d) After the phase inversion in iteration 2?

- α101=
- αx for x ≠ 101 =

(e) After the inversion about mean in iteration 2?

- α101=
- αx for x ≠ 101 =

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Anyone please?
a) 1/sqrt(8), 1/sqrt(8)
b) -1/sqrt(8), 1/sqrt(8)
c) 5/(2*sqrt(8)), 1/(2*sqrt(8))
d) -5/(2*sqrt(8)), 1/(2*sqrt(8))
e) 22/(8*sqrt(8)), -1/(4*sqrt(8))
Thanks Anonymous!
q5 pls
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Problem 5 please?
Problem 5 Please?
P5 plz??
Consider a deuteron in a cyclotron with field strength 0.5T. The deuteron is accelerated twice per rotation by a potential of V=25 kV. (a) If the radius of the cyclotron is 2 meter, what is the maximum energy of the deuteron? Express your answer in Joules (the deuteron mass is 3.34×10−27kg) b)Starting from a negligibly small velocity, how many full rotations does the deuteron need before it reaches this maximum energy? c) What is the time it takes for the deuteron to make one complete rotation when its energy is about 500 keV and when it is about 5 MeV? Ignore possible relativistic effect
q6) 1
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