Let ๐‘† be the region (in the first quadrant) bounded by a circle ๐‘ฅ^2 + ๐‘ฆ^2 = 2, ๐‘ฆ^2 = ๐‘ฅ and the ๐‘ฅ-axis

(ii) Find the volume of the solid generated by rotating the region ๐‘† about the ๐‘ฆ-axis
(c) Find the surface area of the solid generated by rotating the region ๐‘† about the ๐‘ฅ-axis.
๏ฟผ๏ฟผ๏ฟผ
๏ฟผ๏ฟผ

1 answer

(i)
v = โˆซ[0,1] ฯ€(R^2-r^2) dy
where R^2=2-y^2 and r=y^2

(ii)
v = โˆซ[0,1] 2ฯ€rh dy
where r=y and h=โˆš(2-y^2)-y^2