E[x^2] = (1/9)β«0^3 (4x^2 - x^3) dx = (1/9) (16/3 - 1) = 5/9
var[X] = E[x^2] - (E[x])^2 = 5/9 - (1.75)^2 = 0.84375
Let π be a random variable with density
π(π₯)={πΆ(4π₯βπ₯^2) , 0β€π₯β€3
0 , otherwise
where πΆβπ is some constant.
C = 1/9
E[X] = 1.75
Find E[x^2] (the second order moment of π) = ??
Find var[π], the variance of the random variable π = ??
1 answer