The resulting equation after rewriting in terms of a is:
a^2 + 32 = 12a + 48
Rearranging this equation:
a^2 - 12a + 16 = 0
Therefore, the coefficient of the a term is -12 and the constant is 16.
Let a = x^2 + 4. Rewrite the following equation in terms of a and set it equal to zero.
(x^2+4)^2+32= 12x^2 + 48
In resulting equation what is the coefficient of the a term?
In the resulting equation, what is the constant?
1 answer