Let a=x^2+4. Rewrite the following equation in terms of a and set it equal to zero.

Question

(x^2+4)^2+32=12x^2+48

In the resulting equation what is the coefficient of the a term? In the resulting equation, what is the constant?

Answer 1

First, let's rewrite the equation in terms of a:

a^2 + 32 = 12a + 48

Now, we can rewrite this equation as a quadratic equation in terms of a:

a^2 - 12a + 16 = 0

In this quadratic equation, the coefficient of the a term is -12 and the constant is 16.