just do what you always do. It does not matter whether the symbols are variables or constants.
a(x+y) + bz + c = d
ax + ay = d-bz-c
ax = d-ay-bz-c
x = (d-ay-bz-c)/a
Clearly, a cannot be zero. Otherwise, all's fair in love and algebra.
Let a, b, c and d all be real numbers and let x, y and z be variables. What is the solution (solve for x) to the equation a(x+y) + bz + c = d and state any restrictions (you cannot divide by zero).
I'm lost for this... Can someone help me?
1 answer