Let (7,-3) be a point on the terminal side of theta. Find the exact values of cos of theta, sec of theta and cot of theta?

Answer 1

r^2= 7^2 + (-3)^2 = 58
r = √58

since (7,-3) is in IV,
cosØ = 3/√58
secØ = √58/3
cotØ = -7/3