Let π‘‹βˆΌπ–€π—‘π—‰(πœ†), πœ†>0. What is the moment generating function (MGF) 𝑀𝑋(𝑑) of 𝑋?

exp(βˆ’πœ†π‘‘)

πœ†πœ†βˆ’π‘‘βˆ€π‘‘βˆˆβ„

1πœ†

βˆ’πœ†π‘‘βˆ’πœ†βˆ€π‘‘<πœ†

1 answer

The moment generating function of π‘‹βˆΌπ–€π—‘π—‰(πœ†) is 𝑀𝑋(𝑑) = 1/(1-πœ†π‘‘), 𝑑<1/πœ†.

To see this, we can use the definition of the moment generating function:

𝑀𝑋(𝑑) = 𝔼[𝑒^𝑑𝑋]

= βˆ«β‚€^∞ e^𝑑π‘₯ πœ†e^βˆ’πœ†π‘₯ dx (since 𝑋 has an exponential distribution with parameter πœ†)

= πœ† βˆ«β‚€^∞ e^(𝑑-πœ†)π‘₯ dx

= πœ†/(πœ†-𝑑), 𝑑<πœ†.

Therefore, the moment generating function of 𝑋 is 1/(1-πœ†π‘‘), 𝑑<1/πœ†.