To find the area of triangle ABC with vertices A (-5, -4), B (3, -3), and C (3, 2), we can use the formula for the area of a triangle based on the coordinates of its vertices:
\[ \text{Area} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right| \]
Here, let \( (x_1, y_1) = (-5, -4) \), \( (x_2, y_2) = (3, -3) \), and \( (x_3, y_3) = (3, 2) \).
Plugging in the coordinates:
\[ \text{Area} = \frac{1}{2} \left| (-5)(-3 - 2) + (3)(2 - (-4)) + (3)(-4 - (-3)) \right| \]
Calculating each term:
- The first term: \((-5)(-5) = 25\)
- The second term: \(3(2 + 4) = 3(6) = 18\)
- The third term: \(3(-4 + 3) = 3(-1) = -3\)
Putting these values back into the area formula:
\[ \text{Area} = \frac{1}{2} \left| 25 + 18 - 3 \right| \] \[ = \frac{1}{2} \left| 40 \right| \] \[ = \frac{1}{2} \times 40 = 20 \]
Thus, the area of Leonardo’s triangle is \( \boxed{20} \) square units.