To find the area of triangle ABC with vertices A (-5, -4), B (3, -3), and C (3, 2), we can use the formula for the area of a triangle given its vertices \((x_1, y_1)\), \((x_2, y_2)\), and \((x_3, y_3)\):
\[ \text{Area} = \frac{1}{2} \left| x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right| \]
Substituting in the coordinates of points A, B, and C:
- \( (x_1, y_1) = (-5, -4) \)
- \( (x_2, y_2) = (3, -3) \)
- \( (x_3, y_3) = (3, 2) \)
Calculating the individual terms:
- \( x_1(y_2 - y_3) = -5(-3 - 2) = -5(-5) = 25 \)
- \( x_2(y_3 - y_1) = 3(2 - (-4)) = 3(2 + 4) = 3(6) = 18 \)
- \( x_3(y_1 - y_2) = 3(-4 - (-3)) = 3(-4 + 3) = 3(-1) = -3 \)
Now, summing these up:
\[ \text{Area} = \frac{1}{2} \left| 25 + 18 - 3 \right| = \frac{1}{2} \left| 40 \right| = \frac{1}{2} \times 40 = 20 \]
Thus, the area of Leonardo's triangle is:
\[ \boxed{20} \text{ square units} \]
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