To solve the problem, we can set up an equation based on the information given about the balance.
Let \( b \) represent the weight of each wooden block in ounces.
From the problem statement, we know that:
On one side of the balance:
- 6 blocks weigh \( 6b \) ounces
- Plus a 200-ounce weight makes it \( 6b + 200 \) ounces.
On the other side of the balance:
- 2 blocks weigh \( 2b \) ounces
- Plus a 500-ounce weight makes it \( 2b + 500 \) ounces.
Since the balance is even, we can set the two sides equal to each other:
\[ 6b + 200 = 2b + 500 \]
Now, we can solve for \( b \):
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Subtract \( 2b \) from both sides: \[ 6b - 2b + 200 = 500 \] \[ 4b + 200 = 500 \]
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Subtract 200 from both sides: \[ 4b = 300 \]
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Divide both sides by 4: \[ b = \frac{300}{4} = 75 \]
Thus, each wooden block weighs 75 ounces.