First, let's find the perimeter of the original triangle.
You mentioned the lengths of the legs of the triangle: one leg is 7, the other leg is 24, and the hypotenuse is 25.
To find the perimeter of the original triangle, we simply add the lengths of all three sides:
\[ \text{Perimeter} = 7 + 24 + 25 = 56 \text{ cm} \]
Now, if the triangle is dilated using a scale factor of 2, all sides will be multiplied by 2:
\[ \text{Dilated perimeter} = 2 \times 56 = 112 \text{ cm} \]
Therefore, the perimeter of the dilated triangle is 112 cm.
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